Question Bank • QB_SWCE_EXP_035 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Soil and Water Erosion

Subtopic: Vegetative waterways

Question Statement:

A parabolic vegetative waterway has a top width $T = 6.0\text{ m}$ and center depth $y = 0.60\text{ m}$. The cross-sectional flow area $A$ in $\text{m}^2$ is ________ (round off to 2 decimal places).

Answer Key:

2.4

Step-by-Step Solution & Explanation

For a parabolic channel: $A = \frac{2}{3} T y$ Given $T = 6.0\text{ m}$ and $y = 0.60\text{ m}$: $A = \frac{2}{3} \times 6.0 \times 0.60 = 4.0 \times 0.60 = 2.40\text{ m}^2$
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