Question Statement:
According to the Mean Value Theorem, if $f(x) = x^2$ on $[1, 3]$, the point $c \in (1, 3)$ where $f'(c) = \frac{f(3) - f(1)}{3 - 1}$ is:
Options:
- (A) $2$
- (B) $1.5$
- (C) $2.5$
- (D) $\sqrt{3}$
Section 1: Engineering Mathematics
Subtopic: Limit, continuity and differentiability
Options:
Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.
Launch CBT Mock Test