Allied & ICAR Exam Bank • ALLIED_0043 NAT • 2 Marks

Section 1: Engineering Mathematics

Calculus

Subtopic: Limit, continuity and differentiability

Question Statement:

The value of the improper integral $\int_0^\infty e^{-3x} dx$ is:

Answer Key:

0.333

Step-by-Step Solution & Explanation

$\left[ -\frac{e^{-3x}}{3} \right]_0^\infty = 0 - \left( -\frac{1}{3} \right) = \frac{1}{3} \approx 0.333$.
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