Allied & ICAR Exam Bank • ALLIED_1312 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Thermal Processing and Kinetics

Subtopic: Arrhenius Activation Energy

Question Statement:

The thermal degradation rate constant of thiamine in liquid milk at $100^\circ\text{C}$ (373 K) is $k_1 = 0.01\text{ min}^{-1}$ and at $120^\circ\text{C}$ (393 K) is $k_2 = 0.04\text{ min}^{-1}$. Given universal gas constant $R = 8.314\text{ J/(mol}\cdot\text{K)}$ and $\ln(4) = 1.3863$, the activation energy $E_a$ in kJ/mol using Arrhenius equation $\ln(k_2/k_1) = \frac{E_a}{R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)$ with $\left(\frac{1}{373} - \frac{1}{393}\right) = \frac{20}{146589} = 1.3643 \times 10^{-4}\text{ K}^{-1}$ is:

Answer Key:

84.5

Step-by-Step Solution & Explanation

$1.3863 = \frac{E_a}{8.314} \times (1.3643 \times 10^{-4}) \implies E_a = \frac{1.3863 \times 8.314}{1.3643 \times 10^{-4}} = \frac{11.5257}{1.3643 \times 10^{-4}} \approx 84,480\text{ J/mol} = 84.48\text{ kJ/mol}$.
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