Subtopic: Fluidization of granular solids – pneumatic, bucket, screw and belt conveying
Question Statement:
A flat belt conveyor carries grain of bulk density $750\text{ kg/m}^3$ at a speed of $1.5\text{ m/s}$. The cross-sectional area of the grain pile on the belt is $0.02\text{ m}^2$. Calculate the conveying capacity of the belt in $\text{tonnes/h}$.
Answer Key:
81
Step-by-Step Solution & Explanation
Mass flow rate:
$\dot{m} = A \times v \times \rho = 0.02\text{ m}^2 \times 1.5\text{ m/s} \times 750\text{ kg/m}^3 = 22.5\text{ kg/s}$
In tonnes per hour:
$\text{Capacity} = \frac{22.5 \times 3600}{1000} = 81.0\text{ tonnes/h}$