Question Bank • QB_APE_EXP_101 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Material Handling

Subtopic: Fluidization of granular solids – pneumatic, bucket, screw and belt conveying

Question Statement:

A screw conveyor is inclined at an angle of $20^\circ$ to the horizontal. Due to the inclination, its conveying capacity drops to $75\%$ of its horizontal rated capacity of $24\text{ m}^3/\text{h}$. Calculate the inclined capacity in $\text{m}^3/\text{h}$.

Answer Key:

18

Step-by-Step Solution & Explanation

$Q_{\text{inclined}} = Q_{\text{horizontal}} \times 0.75 = 24 \times 0.75 = 18.0\text{ m}^3/\text{h}$
← Previous (QB_APE_EXP_081) Next (QB_APE_MAT_001) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test