Question Bank • QB_DFE_EXP_045 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Refrigeration and cold storage basics and applications

Question Statement:

An ideal Carnot refrigeration cycle operates between an evaporator temperature of $-13.0^\circ\text{C}$ ($260\text{ K}$) and a condenser temperature of $+27.0^\circ\text{C}$ ($300\text{ K}$). The Carnot Coefficient of Performance ($COP_{Carnot} = \frac{T_L}{T_H - T_L}$) is ________ (round off to 1 decimal place).

Answer Key:

6.5

Step-by-Step Solution & Explanation

Carnot COP formula: $COP_{Carnot} = \frac{T_L}{T_H - T_L} = \frac{260\text{ K}}{300\text{ K} - 260\text{ K}} = \frac{260}{40} = 6.50$
← Previous (QB_SUB_DFE_REF_002) Next (QB_DFE_EXP_048) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test