Question Bank • QB_DFE_EXP_048 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Refrigeration and cold storage basics and applications

Question Statement:

In a vapor compression refrigeration cycle using R-134a, the refrigerant enters the compressor as saturated vapor with enthalpy $h_1 = 390.0\text{ kJ/kg}$ and leaves the compressor with enthalpy $h_2 = 425.0\text{ kJ/kg}$. The refrigerant leaves the condenser as saturated liquid with enthalpy $h_3 = 240.0\text{ kJ/kg}$. If the expansion process is isenthalpic ($h_4 = h_3$), the COP of the cycle is ________ (round off to 2 decimal places).

Answer Key:

4.29

Step-by-Step Solution & Explanation

1. Refrigeration effect $q_{evap} = h_1 - h_4 = 390.0 - 240.0 = 150.0\text{ kJ/kg}$. 2. Compressor work $w_{comp} = h_2 - h_1 = 425.0 - 390.0 = 35.0\text{ kJ/kg}$. 3. Coefficient of Performance: $COP = \frac{q_{evap}}{w_{comp}} = \frac{150.0\text{ kJ/kg}}{35.0\text{ kJ/kg}} = \frac{30}{7} \approx 4.2857 \approx 4.29$
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