Question Bank • QB_EXP_DFE_HEX_040 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Heat Exchangers: LMTD & NTU-Effectiveness Methods

Subtopic: Counterflow heat exchanger LMTD calculation

Question Statement:

Referring to the temperature profile, milk flows at $1.5\text{ kg/s}$ ($c_p = 3.9\text{ kJ/(kg}\cdot\text{K)}$) and is cooled from $85^\circ\text{C}$ to $40^\circ\text{C}$. Calculate the total heat load $Q$ transferred in $\text{kW}$ (round off to one decimal place).

Answer Key:

263.25

Step-by-Step Solution & Explanation

$Q = m c_p \Delta T = 1.5 \times 3.9 \times (85 - 40) = 5.85 \times 45 = 263.25\text{ kW}$.
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