Question Bank • QB_FM_132 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A tractor working with a 3-bottom plow plows an area of $3.6\text{ ha}$ in $6.0\text{ hours}$ of total field time. Calculate the effective field capacity in $\text{ha/h}$.

Answer Key:

0.6

Step-by-Step Solution & Explanation

$EFC = \frac{\text{Area}}{\text{Time}} = \frac{3.6\text{ ha}}{6.0\text{ h}} = 0.60\text{ ha/h}$
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