Question Bank • QB_FM_145 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A combine harvester with a $4.0\text{ m}$ cutter bar operates at a forward speed of $3.6\text{ km/h}$. The field efficiency of the harvesting operation is $75\%$. Calculate the effective field capacity in $\text{ha/h}$.

Answer Key:

1.08

Step-by-Step Solution & Explanation

Theoretical field capacity: $TFC = \frac{W \times v}{10} = \frac{4.0\text{ m} \times 3.6\text{ km/h}}{10} = 1.44\text{ ha/h}$ Effective field capacity: $EFC = TFC \times \eta_f = 1.44 \times 0.75 = 1.08\text{ ha/h}$
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