Question Bank • QB_SUB_FP_TRS_002 NAT • 2 Marks

Section 3: Farm Power

Tractors and Power Tillers

Subtopic: Power transmission systems – gear trains, differential, final drives and power take-off

Question Statement:

In a tractor differential unit during a sharp turn, the crown wheel rotates at $120\text{ rpm}$. If the inner drive wheel rotates at $90\text{ rpm}$, the rotational speed of the outer drive wheel (in rpm) is:

Answer Key:

150.0

Step-by-Step Solution & Explanation

Differential relationship: $N_{\text{ring}} = \frac{N_1 + N_2}{2}$ $120 = \frac{90 + N_2}{2} \implies 240 = 90 + N_2 \implies N_2 = 150.0\text{ rpm}$
← Previous (QB_FP_ADV_074) Next (QB_FP_019) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test