Question Bank • QB_SWCE_ADV_155 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Soil and Water Erosion

Subtopic: Soil loss estimation

Question Statement:

The Modified Universal Soil Loss Equation (MUSLE) estimates storm event sediment yield as: $Y = 11.8 (Q \cdot q_p)^{0.56} \times K \cdot LS \cdot C \cdot P$, where $Y$ is sediment yield in metric tons, storm runoff volume $Q = 25,000\text{ m}^3$, and peak runoff rate $q_p = 4.0\text{ m}^3/\text{s}$. Given $K = 0.035$, $LS = 2.0$, $C = 0.15$, and $P = 0.80$. The predicted sediment yield $Y$ in metric tons ($\text{t}$) is ________ (round off to one decimal place).

Answer Key:

62.5

Step-by-Step Solution & Explanation

1. Runoff energy factor $(Q \cdot q_p)$: $Q \cdot q_p = 25,000 \times 4.0 = 100,000\text{ m}^6/\text{s}$ $(100,000)^{0.56} = (10^5)^{0.56} = 10^{2.80} = 630.957$ 2. Watershed soil and management factors product: $\text{Product} = K \times LS \times C \times P = 0.035 \times 2.0 \times 0.15 \times 0.80 = 0.00840$ 3. Total sediment yield $Y$: $Y = 11.8 \times 630.957 \times 0.00840 = 7445.29 \times 0.00840 = 62.54\text{ metric tons} \approx 62.5\text{ t}$
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